Verilog output same as analog output?

When I graph V(q2), output of a Verilog block, but then also the graph of V(out), which is V(q2) after a few passive components, I get exactly the same graph. Is this expected? What’s going on? I would expect V(q2) to be like an independent voltage source, so the load should not matter.

The input and outputs of the Verilog block are type bit vector.

Thanks,
Joe

Refer to this post
C++ DLL Output Issue: Hardcoded 1.0f output appears as ~0.909 (1/1.1) - QSPICE - Qorvo Tech Forum