The formula for calculating the default Rpar value for inductance is not correct

The formula for calculating the default Rpar value for inductance is not correct. L=1Henry ==> Rpar=1Meg is very small!
and L=1mHenry ==> Rpar=1G.
This leads to the fact that it is not possible to use models for quartz resonators that other spice programs successfully calculate. It is necessary to set Gmin=0, but this is not always acceptable!

I think it’s hard to find an inductor with less parallel loss than the minimum added by default in QSPICE.

But if you don’t like QSPICE’S help on this, you can add an attribute “Rpar=0” to the inductor.

You might want to do the same for the capacitors.

Look at how your default settings are not properly affecting the operation of the transformers. 100 Henry is a very real inductance. I have encountered a microphone amp with 300 Henry.
By the way, I found that the primary current of the top transformer is incomplete - the current through Rpar is not accounted for.