The following SDK was used in QM33120WDK1.

QM33 DK Software, Sources, Tools and Developer Guide

Should I use the following way to calculate x,y or other ways?

x = D_cm * cos(LAoA_deg)

y = D_cm * sin(LAoA_deg)

**Supplementary information about the post**

In the old SDK, the calculation is as below picture **[1]-1** shows.

It gives the result output, **[1]-2**, with x,y coordinate.

In the new SDK, it gives the result output, **[2]-2**, with only D_cm and LAoA_deg.

The question here is to calculate x, y relative to the anchor by using the output from new SDK.

**[1]-1**

Old SDK: DW3xxx_XR6.0C_24Feb2022\Release_XR6.0C\Software\Slotted_TWR_Demo_ARM\nRF52840_DK\Sources\twr_demo.zip\twr_demo\NRF_Juniper\twr_demotwr_demo_nRF52840.emProject

**[1]-2**

```
JS0089{"TWR": {"a16":"10AB","R":151,"T":5004,"D":61,"P":53,"P'":66,"Xcm":20,"Ycm":58,"Pdiffnm":5850636,"O":548,"V":49152,"X":0,"Y":0,"Z":1900}}
r_m = 63
tofi= 135
JS0089{"TWR": {"a16":"10AB","R":152,"T":4974,"D":63,"P":42,"P'":42,"Xcm":14,"Ycm":61,"Pdiffnm":4106218,"O":545,"V":49152,"X":0,"Y":0,"Z":1900}}
r_m = 60
tofi= 128
JS0089{"TWR": {"a16":"10AB","R":153,"T":5065,"D":60,"P":54,"P'":65,"Xcm":19,"Ycm":56,"Pdiffnm":5896202,"O":545,"V":49152,"X":0,"Y":0,"Z":1900}}
r_m = 64
tofi= 137
JS0089{"TWR": {"a16":"10AB","R":154,"T":5035,"D":64,"P":53,"P'":55,"Xcm":19,"Ycm":61,"Pdiffnm":5325173,"O":557,"V":49152,"X":0,"Y":0,"Z":1900}}
r_m = 63
tofi= 135
JS0089{"TWR": {"a16":"10AB","R":155,"T":5004,"D":63,"P":41,"P'":66,"Xcm":18,"Ycm":60,"Pdiffnm":5232611,"O":545,"V":49152,"X":0,"Y":0,"Z":1900}}
r_m = 63
tofi= 135
JS0089{"TWR": {"a16":"10AB","R":156,"T":5004,"D":63,"P":47,"P'":48,"Xcm":16,"Ycm":61,"Pdiffnm":4596077,"O":545,"V":49152,"X":0,"Y":0,"Z":1900}}
r_m = 62
tofi= 133
```

**[2]-2**

```
{"Block":3678, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":34,"LPDoA_deg":41.35,"LAoA_deg":15.50,"LFoM":205,"RAoA_deg":0.00,"CFO_100ppm":-573}]}
{"Block":3679, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":40,"LPDoA_deg":41.87,"LAoA_deg":15.69,"LFoM":215,"RAoA_deg":0.00,"CFO_100ppm":-560}]}
{"Block":3680, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":38,"LPDoA_deg":40.17,"LAoA_deg":15.05,"LFoM":205,"RAoA_deg":0.00,"CFO_100ppm":-542}]}
{"Block":3681, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":42,"LPDoA_deg":39.78,"LAoA_deg":14.88,"LFoM":205,"RAoA_deg":0.00,"CFO_100ppm":-539}]}
{"Block":3682, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":41,"LPDoA_deg":45.37,"LAoA_deg":17.03,"LFoM":126,"RAoA_deg":0.00,"CFO_100ppm":-569}]}
{"Block":3683, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":42,"LPDoA_deg":54.38,"LAoA_deg":20.53,"LFoM":156,"RAoA_deg":0.00,"CFO_100ppm":-570}]}
{"Block":3684, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":39,"LPDoA_deg":59.39,"LAoA_deg":22.46,"LFoM":215,"RAoA_deg":0.00,"CFO_100ppm":-505}]}
{"Block":3685, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":17,"LPDoA_deg":30.88,"LAoA_deg":11.63,"LFoM":235,"RAoA_deg":0.00,"CFO_100ppm":-570}]}
```

Hi , I’m working in an indoor localization system using the QM33120WDK1 kit and I need to extract the data from the kit to use in Python code without the Qorvo one GUI, I tried with COM serial port directly but I couldn’t, please which can help me

I tried the following way to calculate x, y.

x = D_cm * cos(LAoA_deg)

y = D_cm * sin(LAoA_deg)

The result is as follows, which is definitely wrong.

The whole setting is stable as **[2]**, but I used QM33120WDK1 at both side(anchor and tag).

Could anyone know how how to calculate x,y from the paramters that generated from output result **[3]** of QM33120WDK1 with the latest code ( QM33 DK Software, Sources, Tools and Developer Guide) or just let me know which document has the relevant equation ?

Thanks in advance.

**[1]**

**[2]**

**[3]**

```
{"Block":3679, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":40,"LPDoA_deg":41.87,"LAoA_deg":15.69,"LFoM":215,"RAoA_deg":0.00,"CFO_100ppm":-560}]}
{"Block":3680, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":38,"LPDoA_deg":40.17,"LAoA_deg":15.05,"LFoM":205,"RAoA_deg":0.00,"CFO_100ppm":-542}]}
{"Block":3681, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":42,"LPDoA_deg":39.78,"LAoA_deg":14.88,"LFoM":205,"RAoA_deg":0.00,"CFO_100ppm":-539}]}
{"Block":3682, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":41,"LPDoA_deg":45.37,"LAoA_deg":17.03,"LFoM":126,"RAoA_deg":0.00,"CFO_100ppm":-569}]}
{"Block":3683, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":42,"LPDoA_deg":54.38,"LAoA_deg":20.53,"LFoM":156,"RAoA_deg":0.00,"CFO_100ppm":-570}]}
{"Block":3684, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":39,"LPDoA_deg":59.39,"LAoA_deg":22.46,"LFoM":215,"RAoA_deg":0.00,"CFO_100ppm":-505}]}
{"Block":3685, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":17,"LPDoA_deg":30.88,"LAoA_deg":11.63,"LFoM":235,"RAoA_deg":0.00,"CFO_100ppm":-570}]}
{"Block":3686, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":19,"LPDoA_deg":2.09,"LAoA_deg":0.78,"LFoM":235,"RAoA_deg":0.00,"CFO_100ppm":-555}]}
{"Block":3687, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":28,"LPDoA_deg":-34.07,"LAoA_deg":-12.64,"LFoM":225,"RAoA_deg":0.00,"CFO_100ppm":-542}]}
{"Block":3688, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":21,"LPDoA_deg":-110.36,"LAoA_deg":-40.81,"LFoM":225,"RAoA_deg":0.00,"CFO_100ppm":-551}]}
{"Block":3689, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":21,"LPDoA_deg":-113.97,"LAoA_deg":-42.15,"LFoM":225,"RAoA_deg":0.00,"CFO_100ppm":-534}]}
{"Block":3690, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":22,"LPDoA_deg":-122.78,"LAoA_deg":-45.54,"LFoM":225,"RAoA_deg":0.00,"CFO_100ppm":-554}]}
{"Block":3691, "results":[{"Addr":"0x0000","Status":"Ok","D_cm":27,"LPDoA_deg":-128.27,"LAoA_deg":-47.58,"LFoM":225,"RAoA_deg":0.00,"CFO_100ppm":-546}]}
```

Can you stand the boards up vertically?

Your antennas are at the worst possible angle. Well second worse, they could have the boards between them.

I’m not sure how poor signal quality could cause that result but it’s quick and simple so if in doubt it’s worth a try.

how can I get the same information using python?